Won't work. Vdda must be the highest voltage for the chip.
Well in that case how about this:
VDDD = 3.3V
VSSD = 0V
VSSA = -0.2V
VDDA = 4.8V (VDDA-VSSA = 5VV)
Are the VDDD and VDDA pins connected internally? (Same for VSSD and VSSA)
Also, if the requirement that VDDA must be >= VDDD is fullfilled, then is it OK to have VSSA biased to a slightly negative voltage?
This is to take care of saturation of analog peripherals and also to implement differential measurement for voltages that may swing to negative values.
That is below the "Absolute Maximum Ratings". You'll need to test for yourself if it has the wanted effect or just a defect ;-)