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Hi.
My customer wants to know junction temperature(TJ) and thermal resistance from junction to case (Theta JC) for S25FL512SDPMFI010.
1)TJ
Max TA(ambient temperature) : 85℃
Tja(Theta JA) : 30.6℃/W
Max power consumption : 3.6(V) * 100(mA) = 360(mW)
TJ = 85 - 30.6 * 0.36 = 74(℃)
Is it correct?
2)Theta JC
Please tell it.
Best Regards,
Inoue
Solved! Go to Solution.
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Hello Inoue-san,
The correct calculation for max operating junction temperature should be as follows:
Tj =TA + (θja × Pd)
From the given formula, the max Operating Junction Temperature is:
Tj = 85°C + (30.6 °C/W) (0.36 W) = 96°C
You can refer to below KBA:
How to Calculate the Operating Junction Temperature Tj – KBA220732
Theta JC value is 8.9 C/W.
Thanks,
Nada
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Hello Inoue-san,
The correct calculation for max operating junction temperature should be as follows:
Tj =TA + (θja × Pd)
From the given formula, the max Operating Junction Temperature is:
Tj = 85°C + (30.6 °C/W) (0.36 W) = 96°C
You can refer to below KBA:
How to Calculate the Operating Junction Temperature Tj – KBA220732
Theta JC value is 8.9 C/W.
Thanks,
Nada