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Understand when using a Bootloadable component we cannot do debug (tabs grayed out). Simple fix is disable component.
Is there a way to include a boolean operator in the Built-In>Settings>Disable tab to do this on build settings? Such as if we are in Debug mode disable the bootloadable, and in Release mode enable? Just worried when we go to deploy we will forget to include the bootloader. Thanks - CB
Solved! Go to Solution.
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PSoC 5LP
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Hello Clint,
CY_REMOVE is internally used by the PSoC Creator on elaboration stage, before the compilation step. This define [in C#] is not accessible to source code. Hence, there is no option to give this via build settings. For debugging bootloadable project, please enable or disable the bootloadable component in TopDesign.
Best Regards,
Geona Mary
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I believe that Buil-in->CY_REMOVE->True will disable the component.
/odissey1
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Hello Clint,
CY_REMOVE is internally used by the PSoC Creator on elaboration stage, before the compilation step. This define [in C#] is not accessible to source code. Hence, there is no option to give this via build settings. For debugging bootloadable project, please enable or disable the bootloadable component in TopDesign.
Best Regards,
Geona Mary
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G just to be clear I am not looking do anything with CY_REMOVE and unsure why people are focused on this.I have no idea where CY_REMOVE is even used or what it is used for.
I am looking to use the build setting at the red arrow
to affect this setting (pre compilation)
Through this boolean equation accessed
when I click on the f(x) to disable the bootloadable component like this
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Hello Clint,
CY_REMOVE is the parameter name of Disable setting shared in your screenshot. Please make use of appended screen shot.
Best Regards,
Geona Mary