Hello everyone,
i need a clarification on a detail regarding VCCIO=1V8 of CY7C65213.
As seen on the datasheet, the VCCD pin is the OUTPUT of the internal regulator for 1V8 and it cannot drive external loads.
Additionaly, on the datasheet it is mentioned that when VCCIO is less than 2V, VCCD must be connected to VCCIO.
In this scenario, can the device be damaged during startup considering that the default configuration stored in its Flash doesn't disable the internal regulator (as shown on Table 2 in the datasheet)?
Lastly, always from Table 2 of the datasheet, it is hinted that CTS and DSR signals have an internal pull up. What about DCD and RI Signals? Do they have some internal pull up or pull down as well?
Thanks in advance.
Hi,
can the device be damaged during startup considering that the default configuration stored in its Flash doesn't disable the internal regulator (as shown on Table 2 in the datasheet)?
>> Your understanding is correct. It will damage the chip. One need to pre-configure the chip before using it in different configuration.
Lastly, always from Table 2 of the datasheet, it is hinted that CTS and DSR signals have an internal pull up. What about DCD and RI Signals? Do they have some internal pull up or pull down as well?
>> All UART pins have internal pull ups.