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PSoC 4 MCU

Contributor II

Hello,

I want to know why Acutual EEPROM size is twice EEPROM size like below.

pastedImage_0.png

Are there any documents that are explained?

Best regards,

Yocchi

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1 Solution
Employee

Hi Yocchi-San,

The Actual EEPROM size is twice the EEPROM size because the actual size allocated includes an overhead for wear levelling and redundant copy implementations.

You can refer to the below screenshot and this information is present in the Emulated EEPROM (Em_EEPROM) 2.0 Component datasheet - https://www.cypress.com/file/390316/download

pastedImage_0.png

Regards,

Alakananda

Alakananda

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4 Replies
Employee

Hi Yocchi-San,

The Actual EEPROM size is twice the EEPROM size because the actual size allocated includes an overhead for wear levelling and redundant copy implementations.

You can refer to the below screenshot and this information is present in the Emulated EEPROM (Em_EEPROM) 2.0 Component datasheet - https://www.cypress.com/file/390316/download

pastedImage_0.png

Regards,

Alakananda

Alakananda

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Contributor II

Hello Alakananda-san,

Thank you very much for your reply.

Do you have any more details?

Best regards,

Yocchi

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Employee

Hi Yocchi,

This is the information which we have regarding the EEPROM size.

Please let us know if you have any specific queries regarding this.

Regards

Alakananda

Alakananda
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Moderator
Moderator

The actual EEPROM size is larger than user set in EEPROM Size, even though redundant copy is no and wear level factor is none.

Because it requires some internal logic operation for EEPROM Component to simulate the Flash more like a EEPROM other than bare Flash operation.

Best Regards,

Ryan

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