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NaMo_1534561
New Contributor II

Hello,

Please tell me about CY2DL1510AZC's  junction temperature: Tj and package thermal resistance: Θjc.

Best Regards,

Naoaki Morimoto

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1 Solution
ShupingZ_76
Employee

Hi Morimoto-san,

The maximum junction temperature of CY2DL1510AZC is 135°C.

And you can find the thermal resistance of CY2DL1510AZC in the datasheet:

If you want to calculate the operating junction temperature, you could use the following formula:

Tj = TA + (ƟJA)×(Pd)

Where,

          ƟJA = Junction-to-ambient thermal resistance (Theta JA).

          TA = Ambient operating temperature (temperature grade of the actual device)

          Pd = Voltage (V) × Current (I). Typical Voltage and Current values are found in the datasheet

For example, when TA = 55°C, operating voltage V=2.5V, operating current I= 50mA,

then Tj = 55 + 69 x (2.5 x 0.05) = 63.625 °C

You can find more details in KBA220732 and AN201006.

Best regards,

Shuping

View solution in original post

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2 Replies
ShupingZ_76
Employee

Hi Morimoto-san,

The maximum junction temperature of CY2DL1510AZC is 135°C.

And you can find the thermal resistance of CY2DL1510AZC in the datasheet:

If you want to calculate the operating junction temperature, you could use the following formula:

Tj = TA + (ƟJA)×(Pd)

Where,

          ƟJA = Junction-to-ambient thermal resistance (Theta JA).

          TA = Ambient operating temperature (temperature grade of the actual device)

          Pd = Voltage (V) × Current (I). Typical Voltage and Current values are found in the datasheet

For example, when TA = 55°C, operating voltage V=2.5V, operating current I= 50mA,

then Tj = 55 + 69 x (2.5 x 0.05) = 63.625 °C

You can find more details in KBA220732 and AN201006.

Best regards,

Shuping

View solution in original post

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NaMo_1534561
New Contributor II

Hello Shuping-san,

Thank you for your answer.

My question has been solved.

Best Regards,

Naoaki Morimoto

0 Likes