Why digital bank voltage has to be less than analog?

Tip / Sign in to post questions, reply, level up, and achieve exciting badges. Know more

cross mob
Anonymous
Not applicable

The PSoC 3 kit-030 datasheet recommends not to use a VDDD higher than VDDA..... What is the reason for that?

   

Regards.

0 Likes
1 Solution
ETRO_SSN583
Level 9
Level 9
250 likes received 100 sign-ins 5 likes given

The digital control V of an analog transmission gate is limited by gate ox

   

breakdown and parasitic diode turn on in non isolated well chip designs.

   

 

   

Additionally Vgs wants to be as high as possible, within those constraints,

   

to obtain max turn on, thereby resulting in higher switching speed and drive,

   

hence lower power. And to achieve min Rdson where ohmic switch performance

   

is paramount.

   

 

   

The goal of all this is to achieve higher Vg than analog in the transmission gate

   

where possible. Subject to noise feedthru, etc..

   

 

   

Tradeoffs, always tradeoffs.

   

 

   

Regards, Dana.

View solution in original post

0 Likes
7 Replies
HeLi_263931
Level 8
Level 8
100 solutions authored 50 solutions authored 25 solutions authored
        The digital supply voltage can be as high as the analog supply voltage.   
To cite from the PSoC3 Architecture TRM:   
    Vdda must be greater than or equal to all other power supply pins (Vddd, Vddios) in PSoC 3. This power supply condition is required for the proper ON/OFF condition of the analog switches inside the device, and also for the implementation of the internal level switching logic when signals transition between multiple supply voltage domains.   
(page 136)   
ETRO_SSN583
Level 9
Level 9
250 likes received 100 sign-ins 5 likes given

At its most basic level  analog switching and routing govern the basic

   

CMOS analog switch characteristics, as well as device geometry.

   

 

   

Reference -

   

 

   

www.analog.com/library/analogdialogue/archives/31-3/ask.html

   

 

   

There are techniques, like gate drive boost converters, to get high

   

switch gate drive out of low core voltages, but as always tradeoffs

   

are incurred. Boost generaly implies more digital noise coupled

   

thru Cgd, Cgs in the switch.

   

 

   

Regards, Dana.

0 Likes
HeLi_263931
Level 8
Level 8
100 solutions authored 50 solutions authored 25 solutions authored
        This requirements is because you have digital logic controlling analog components (but not vice versa). Think about, e.g., the analog muxes controlled by a control register. It would be bad if the digital voltage would be higher than then analog on - its like applying a too high voltage to an input.   
ETRO_SSN583
Level 9
Level 9
250 likes received 100 sign-ins 5 likes given

The digital control V of an analog transmission gate is limited by gate ox

   

breakdown and parasitic diode turn on in non isolated well chip designs.

   

 

   

Additionally Vgs wants to be as high as possible, within those constraints,

   

to obtain max turn on, thereby resulting in higher switching speed and drive,

   

hence lower power. And to achieve min Rdson where ohmic switch performance

   

is paramount.

   

 

   

The goal of all this is to achieve higher Vg than analog in the transmission gate

   

where possible. Subject to noise feedthru, etc..

   

 

   

Tradeoffs, always tradeoffs.

   

 

   

Regards, Dana.

0 Likes
Anonymous
Not applicable

olryt....so the reason goes deep into the CMOS switching features.......Anyways, I get it...Thanks for explaning this.

   

However, assuming that a certain application requires the digital bank to work at a voltage higher than that of the analog bank...can anything be done in PSoC for this particular case?

   

 

   

Regards.

0 Likes
HeLi_263931
Level 8
Level 8
100 solutions authored 50 solutions authored 25 solutions authored
        You can either run everything on the lower voltage and use level shifter for the digital signals.   
Or you run everything on the higher voltage, use voltage dividers on the analog inputs (if they are needed for some reason) and limit the outputs to the voltage you want.   
Actually I don't see any need for that scenario - what would be a reason tu run the analog section at a lower voltage than the digital one?   
0 Likes
Anonymous
Not applicable

Even I dont need a higher VDDD...but I was just assuming it [you know, hptothetically ]: just in case we need to...!!!!!

   

Regards.

0 Likes