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PSoC 3
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The OpAmp is rated worst case for a total of 16 mA output source. So
Vddio loads would have to be pretty light. Additionally the OpAmp is a
slow device with regards to transients on its control loop, which Vout
is a part of, so you may get a lot of transients on GPIO pins. And you
cannot bypass Vddio with C as it would probably put the OpAmp into
oscillation as it is not comped for high Cload.
Regards, Dana.
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One solution would be to use a 1.8 volt zener like http://www.diodes.com/datasheets/ds30410.pdf
Or 2 Si diodes = nominal Vddio 3.4V, all depends on I/O loads and what you
are driving. Clearly nosie margin is of concern, and meeting I/O load specs.
You would have to worst case the design.
Regards, Dana.
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Is the 3.3V circuit you are using already powered with 3.3V?
I'm not sure whether its allowed at all to power the PSoCs VddIO line from within itself. You would need to be careful thatthe VddIO you are powering has no dependency to the part providing this power...
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Just to be clear the recomendations I gave are assuming, as stated in
original post, that you are using an external 5 V supply, so my comments
about use of a zener or two Si diodes are to obtain power from that 5 V
external supply fed to the zener or diodes acting as semi regulated Vdrop
to derive the ~ 3.3V.
Again, I recommend you do NOT use OpAmp for the following reasons -
1) Transients on Vddio causing OpAmp to fall out of regulation.
2) External CMOS input loads drawing power because OpAmp excessive recovery
time to a transient leaving external CMOS loads (inputs) that will cause N & P transistors
in the inputs to both conduct for some period of time = large system currents..
3) You cannot bypass Vddio because OpAmp not comped for large Cload.
4) Degraded noise margin as OpAmp output is not R-R.
The optimal best simple approach, use a LDO off the 5 V supply. One that can handle
large Cload. Better yet, a switcher for better efficiency.
Regards, Dana.
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If your external circuit has already a 3.3V power supply, you can use this one to power to VddIO you need for interfacing to it.
Or yu can use SIO pins for the interface. Then you can set their output level to 'Vref', and power the reference by the DAC internally.
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Not so sure you want to do that based on drive levels from SIO -
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Why? Its about driving logic inputs, so I expect some microamps flowing there...
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"Why? Its about driving logic inputs, so I expect some microamps flowing there..."
I was not aware of what the loads were, so thinking a mix of logic, LED,.....
And of course you are still trying to supply loads via an OpAmp output, comped for
unity gain I might add, amongst other issues, which is not going to handle transients
well. Really not a good solution.
Below representative example of what 1 Mhz switching might look like....
Dana.
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Just a second: so we aren't talking about outputs which should drive 3.3V logic? YOu have an external 5V circuit which, somehow, produces just 3.3V output signals?
That should be no problem, the signal level for 3.3V signals can, in most cases, be properly handled by 5V inputs. You need to check the data sheets of your RC receiver what the lowest guaranteed voltage level for 'high' is - if its above what the PSoC needs to read it as high, you are fine. Then there is no need to drive Vddio with a different voltage.
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The original post -
"Hi. I'm designing circuit using CY8C3446LTI-083 which has only 5V supply and have to interface 3.3V system (I need vddio0 to be 3.3V)."
Not sure I understand your point.
Regards, Dana.
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Now I found that input threshold can be set to LVTTL for gpio pins. I thought only CMOS is available but it was wrong. This makes the threshold 2V so I think I can go with single 5V.
Thanks for help you all
Regards, kmiya0118
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@dana: the original statement "needing Vddio=3.3V" implied to me (and to you as well, judging by the first answers) that we are talking about driving a significant load. Thats why the hesitation about OpAmps, and the recommendation about SIO pins came up.
But when its only about having inputs which need to handle 3.3V-level-logic, then its a completely different picture. And as kmiya found out, its much simpler to solve...
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I concur, if the receiver does not need any control signals.
Regards, Dana.