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Hİ,
I designed new circuit using CY8C3866AXI-040. Due to an error, when trying to install the program chip can not be found. I followed the rules of the circuit design psoc3 but chip can't be found. Then I searched for the error. I found that VDDD voltage> VDDA voltage. I measuered VDDD voltage 0.7 V. VDDA voltage is 5.2 V. So chip can't be found. When I equal to voltages with jumpers. IC quickly is heating. I could not find the cause of warming. I attach design file. Can you look at design. When VDDD = VDDA , what is the cause of warming of IC. Thanks.
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I can't figured out the cause of ploblem from picture of board and schematic.
I guess, does some pins that has a voltage was grounded?
Vddd is doubtful I think.
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If chip is getting hot most common problem is latchup, some thoughts -
1) Latchup occurs when a pin is taken outside power supply voltage, eg.
Vssd,Vssa > pin or pin > Vddd, Vdda. Then chip internally has a parasitic SCR
trigger shorting Vdd to Vss, and draws a lot of current obviously.
Question, chip getting hot immeadiatley, power supply showing high currents
immeadiately, or after CPU well into code ? Code your processor to just start,
but do nothing, sit in a loop immeadiately, right after startup. If Idd does not jump
to latchup condition then power system probably OK. Then suspect processor
GPIO triggering some load causing a transient on a pin outside supply rails.
2) You have a relay, I cannot see drive coil on schematic, I assume Q1 is driving it
and D50 is strapped across coil to suppress turnoff transients ? Check Q1 collector
with scope, to see it never transients outside Vddd, Vdda or < Vssd,a. Set scope
up to trigger on 5.5 initially, then - .5, to see if you ever get a transient outside power
supply rails. If your scope has deep memory trigger off init of power supply and look
at each pin (tedious) to see if you can qualify a trigger outside supplie rails.
3) Look at ground points around board, trigger off main ground reference , -.5, to
see if you can get a trigger. This is difficult as you would need to cycle power each time
you look at a new pin.
Some thoughts, Dana.