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Hi,
On a PRoC BLE, we can configure a GPIO in Open Drain, pulls low. What is the maximum voltage we can put on the pin and sink?
E.g. if VCC is 1.8V, can we sink a 3.3V LED? The electrical characteristics mentions one thing to do with GPIOs - a tolerance of +0.5V, and as a digital input I can see why that would be, but how about as an Open Drain?
Thanks, Dave
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The voltage at any pins cannot be higher than Vcc. So no, you cannot switch a 3.3V load with an output when Vcc is only 1.8V.
The tolerances for the output come from the internal resistance of the output transistors - when you sink the maximum current through them they have a dropout voltage of 0.5V.
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The voltage at any pins cannot be higher than Vcc. So no, you cannot switch a 3.3V load with an output when Vcc is only 1.8V.
The tolerances for the output come from the internal resistance of the output transistors - when you sink the maximum current through them they have a dropout voltage of 0.5V.
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ok, Thanks.
We decided this was the case and so have designed with this in mind.