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This may be simpler than I think it is, but I just do not remember how to do this and could not find other topics.
I have an int16. I print the value on UART display. I want to format that into two int8 (maybe an array) and print them again on UART, then later on, recombine the two int8 into one and print the value again. The combined value of the two int8 would be the original int16. How would I do this?
I imagine it would require some bit shifting, but I just cannot remember how to do this.
Solved! Go to Solution.
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Other way:
uint16 V = 0xABCD; // set value
uint8 msb = (V>>8); // get MSB (0xAB)
uint8 lsb = V; // get LSB (0xCD)
Same, but fancy way
uint16 V = 0xABCD; // set value
uint8 msb = (V>>8) & 0xFF; // get MSB (0xAB)
uint8 lsb = V& 0xFF; // get LSB (0xCD)
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Something like this:
Union TypeCombined {
uint16 val;
struct { // anonimous structure
uint8 lsb;
uint8 msb;
}
} myVal;
myVal.val = 0xABCD; // set some value
uint8 a = myVal.lsb; // get LSB (0xCD)
uint8 b = myVal.msb; // get MSB(0xAB)
Opposite works also:
myVal.lsb = 0x23; //set lsb
myVal.msb = 0x01; // set msb
Get result:
uint v = myVal.val; // (0x0123)
This way you can go back and forth between the val and {msb, lsb}.
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Other way:
uint16 V = 0xABCD; // set value
uint8 msb = (V>>8); // get MSB (0xAB)
uint8 lsb = V; // get LSB (0xCD)
Same, but fancy way
uint16 V = 0xABCD; // set value
uint8 msb = (V>>8) & 0xFF; // get MSB (0xAB)
uint8 lsb = V& 0xFF; // get LSB (0xCD)
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When I want to recombine that, how would that line be written?
EDIT: nevermind figured that out. Thank you again!