Cypress BLE-Beacon IOS source code

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Anonymous
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Hello everyone,

   

I am trying to locate the source code for BLE-Beacon IOS app. Has anyone worked with it?

   

Thanks,
Apoorva

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1 Solution
AnjanaM_61
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5 comments on KBA First comment on KBA 5 questions asked

Hello Apoorva,

   

Please find the  source code for BLE Beacon iOS app from the below link:

   

https://www.dropbox.com/s/ifdfa9dkuvy1w3z/CypressBLE-Beacon_iOS_1.0.0_9.zip?dl=0

   

Thanks,
Anjana

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6 Replies
AnjanaM_61
Moderator
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5 comments on KBA First comment on KBA 5 questions asked

Hello Apoorva,

   

Please find the  source code for BLE Beacon iOS app from the below link:

   

https://www.dropbox.com/s/ifdfa9dkuvy1w3z/CypressBLE-Beacon_iOS_1.0.0_9.zip?dl=0

   

Thanks,
Anjana

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Anonymous
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Hello,

I know this app with the version 1.2.0 is published,and I tried launch in iOS11.

And I can launch the app with the version 1.2.0.

Then Would you give me this version's source code?

Thanks,

Naruki

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Anonymous
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Thank you so much Anjana. 

   

Best, Apoorva

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Anonymous
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Anjana, I am unable to compile this code. An error "nullability specifier conflicts with existing specifier nonnull" pops up. I believe that error is because I am using xcode Version 8.2.1 (8C1002) which incompatible with coreplot framework used in this source code. Do you think you could provide an updated version.

   

 

   

Thanks again, Apoorva

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AnjanaM_61
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5 comments on KBA First comment on KBA 5 questions asked

Hi Apoorva,

   

The source code was developed with XCODE 6.

   

As you know, newest XCODE updates an API design to Swift3.0 (Currently using 2.0).

   

To update from Swift2.0 to 3.0, we need to redesign the APIs. Currently we don't have newest version source code for now.

   

In this time, I recommend to use old XCODE version like XCODE 6.3.2.

   

You can download the old XCODE from

   

https://developer.apple.com/download/more/

   

Thanks & Regards,
Anjana

Anonymous
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Hello Anjana,

   

it is possible to have the source code for CypressBLE-Beacon Android version?

   

Thank you in advance

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