FX3 DVK DEVICE BOARD: REV - 3.0 Schematic Error or ??

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cross mob
Anonymous
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I am currently implementing the FX3 into a project; I have the board and I have the schematics.

   

My problem is that on page 9 of the schematics there seems to be an error, I didn't catch it until just now:

   

On the USB3.0 MICRO -TYPE B connector:

   
        
  • MICRO_SSTX- (connector pin) is connected to SS_TX_M (signal)
  •     
  • MICRO_SSTX+ (connector pin) is connected to SS_TX_P (signal)
  •    
   

the above part makes 100% sense to me.....

   

but the following does not make any sense to me whatsoever

   
        
  • MICRO_SSRX- (connector pin) is connected to SS_RX_P (signal)
  •     
  • MICRO_SSRX+ (connector pin) is connected to SS_RX_M (signal)
  •    
   

Am I missing something? I admittedly did not catch it initially, my experience tells me that

   
        
  • MICRO_SSRX- (connector pin) should be connected to SS_RX_M (signal)
  •     
  • MICRO_SSRX+ (connector pin) should be connected to SS_RX_P (signal)
  •    
   

Is this schematic really representative of the system I have?

   

Any and all input would be greatly appreciated as I am already to the layout stage and hope to have a functional board the first time around.

   

Thanks!

   

-Frank Walker

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1 Solution
Anonymous
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 Hi Frank,

   

I recently ran into the exact same issue. It turns out that it's ok to reverse this pair as polarity detection is done automatically by the PHY. This is done in this case so that the data lines dont have to cross over at all. Check out page 10 of app note AN70707. http://www.cypress.com/?docID=42264

   

David

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4 Replies
Anonymous
Not applicable

 Hi Frank,

   

I recently ran into the exact same issue. It turns out that it's ok to reverse this pair as polarity detection is done automatically by the PHY. This is done in this case so that the data lines dont have to cross over at all. Check out page 10 of app note AN70707. http://www.cypress.com/?docID=42264

   

David

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Anonymous
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I appreciate the effort to respond to my question.

Thank You.
 

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Anonymous
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 You are welcome 

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