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Hello ALL
I used UART component, I kept the buffer size for both tx and rx as 20. So internal interrupt is enabled .we can write the interrupt code in the UART_Int.c file right........
But why does the component provide two interrupt pins to be connected. even though i have not enabled any of the interrupts. i have attached the screen shots..
And second thing , i am using one LCD which takes 6 pins, one for RX and other pin for TX... on building the project the report file says that i have used 12 pins.....and allows me to use only 60 pins out of 72...... what is wrong ...
i have attached all the screeen shots
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PSoC 5LP
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Try disabling debugging pins in DWR -> System -> Programming\Debugging. Then you should see that 9 pins are used (7 by LCD and 2 by UART).
Regards,
Aniruddha
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Try disabling debugging pins in DWR -> System -> Programming\Debugging. Then you should see that 9 pins are used (7 by LCD and 2 by UART).
Regards,
Aniruddha
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Doy you mean to disable Serial wire viewer and Require Xres pin- because these are the things that are enabled in the programming/debugging section....
But what are the side effects ...i cant debug the device ..after disabling them
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When it comes to production of a let's say 1k samples project the pin-count may be of mercantile concern. So having a handful of pins bound to debugging freed (what are they for? its the final production) could give the chance of using a smaller (cheaper) part. Even programming before soldering can save some pins and might enlargen your financal success.
Bob
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Unfortunately for the time being only packages available are
68 QFN and 100 TQFP.
Regards, Dana.
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Yes, what I'd said: When you need one IO-pin more than the 68-pin device offers, you can built the prototype with debug capabilities with the 100-pin device and for the final version switch to the 68-pinner by disabling the debugging capabilities.
Bob
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Understood, just making the point about limited package availability, discussed in
the forums a number of times in the past.
Regards, Dana.